WEAK ACID · HA
Ethanoic acid
Moles HA0.1 mol
MODERNISED TEACHER TOOL
The salt supplies A⁻. The weak acid supplies HA. Because both are in the same final solution, their concentration ratio equals their mole ratio.
Use the equilibrium expression[H⁺] = Kₐ × n(HA) ÷ n(A⁻)
Find [H⁺]7.134 × 10⁻5 mol dm⁻³
Take −log₁₀[H⁺]pH = 4.147